Question

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What volume of liquid h2o2 has same number of molecules as there are number of molecules in 22.4ml h20 at 2 atm and 546k

[Density of liquid h2o2=6.8*10^-3

Answer 1

Answer : The volume of liquid $H_2O_2$ will be, 4.995 L

Explanation :

First we have to calculate the moles of $H_2O$.

Using ideal gas equation,

$PV=nRT$

where,

P = pressure of water gas = 2 atm

V = volume of water gas = 22.4 ml = 0.0224 L

T = temperature of water gas = 546 K

n = number of moles of water gas = ?

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get

$(2atm)\times (0.0224L)=n\times (0.0821L.atm/mole.K)\times (546K)$

$n=9.99\times 10^{-4}mole$

Now we have to calculate the mass of $H_2O_2$.

From the question, we conclude that the number of molecules of $H_2O$ and $H_2O_2$ are same. That means, the moles of $H_2O$ and $H_2O_2$ are also same.

So, the moles of $H_2O_2$ = $9.99\times 10^{-4}mole$

$\text{Mass of }H_2O_2=\text{Moles of }H_2O_2\times \text{Molar mass of }H_2O_2$

$\text{Mass of }H_2O_2=(9.99\times 10^{-4}mole)\times (34g/mole)=33.966\times 10^{-3}g$

Now we have to calculate the volume of $H_2O_2$ liquid.

Formula used :

$\text{Density of }H_2O_2\text{ liquid}=\frac{\text{Mass of }H_2O_2\text{ liquid}}{\text{Volume of }H_2O_2\text{ liquid}}$

Now put all the given values in this formula, we get

$6.8\times 10^{-3}g/L=\frac{33.966\times 10^{-3}g}{\text{Volume of }H_2O_2\text{ liquid}}$

$\text{Volume of }H_2O_2\text{ liquid}=4.995L$

Therefore, the volume of liquid $H_2O_2$ will be, 4.995 L

Answer 2

Answer : The volume of liquid will be, 4.995 L

Explanation :

First we have to calculate the moles of .

Using ideal gas equation,

where,

P = pressure of water gas = 2 atm

V = volume of water gas = 22.4 ml = 0.0224 L

T = temperature of water gas = 546 K

n = number of moles of water gas = ?

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get

Now we have to calculate the mass of .

From the question, we conclude that the number of molecules of and are same. That means, the moles of and are also same.

So, the moles of =

Now we have to calculate the volume of liquid.

Formula used :

Now put all the given values in this formula, we get

Therefore, the volume of liquid will be, 4.995 L