Math, asked by lakshparisp9njhv, 1 year ago

answer for brainliest, with steps.
Two numbers are in the ratio 5:3. If they differ by 18, what are the numbers?

Answers

Answered by siddhartharao77
7
Let the common ratio be x.

Given that two numbers are in the ratio 5:3.

Let the numbers are 5x and 3x

Given that they differ by 18.

= > 5x - 3x = 18

= > 2x = 18

= > x = 9.


1st number = 5 * 9

                    = 45


2nd number = 3 * 9

                     = 27.


Therefore the two numbers are 45 and 27.


Hope this helps!

siddhartharao77: :-)
lakshparisp9njhv: tysm... sure i'll tag u as the brainliest
siddhartharao77: Thank you!...
Answered by Anonymous
1
Hiii!!!

Here's Ur answer...

AtQ, two numbers are in the ratio 5:3 and difference between those two number is 18.

Let the two numbers be 5x and 3x

Therefore 5x - 3x = 18

==> 2x = 18

==> x = 18/2

==> x = 9

Hence, first number = 5x

= 5 × 9

= 45

Second number = 3x

= 3 × 9

= 27

Hope this helps..!!

siddhartharao77: :-)
Anonymous: (-:
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