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Two numbers are in the ratio 5:3. If they differ by 18, what are the numbers?
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Answered by
7
Let the common ratio be x.
Given that two numbers are in the ratio 5:3.
Let the numbers are 5x and 3x
Given that they differ by 18.
= > 5x - 3x = 18
= > 2x = 18
= > x = 9.
1st number = 5 * 9
= 45
2nd number = 3 * 9
= 27.
Therefore the two numbers are 45 and 27.
Hope this helps!
Given that two numbers are in the ratio 5:3.
Let the numbers are 5x and 3x
Given that they differ by 18.
= > 5x - 3x = 18
= > 2x = 18
= > x = 9.
1st number = 5 * 9
= 45
2nd number = 3 * 9
= 27.
Therefore the two numbers are 45 and 27.
Hope this helps!
siddhartharao77:
:-)
Answered by
1
Hiii!!!
Here's Ur answer...
AtQ, two numbers are in the ratio 5:3 and difference between those two number is 18.
Let the two numbers be 5x and 3x
Therefore 5x - 3x = 18
==> 2x = 18
==> x = 18/2
==> x = 9
Hence, first number = 5x
= 5 × 9
= 45
Second number = 3x
= 3 × 9
= 27
Hope this helps..!!
Here's Ur answer...
AtQ, two numbers are in the ratio 5:3 and difference between those two number is 18.
Let the two numbers be 5x and 3x
Therefore 5x - 3x = 18
==> 2x = 18
==> x = 18/2
==> x = 9
Hence, first number = 5x
= 5 × 9
= 45
Second number = 3x
= 3 × 9
= 27
Hope this helps..!!
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