Question

Answer for question 3 and 4

Answer 1

Answer:

3. 500

4. 12

Step-by-step explanation:

3.

(500*400)/(20*20)= 500

4.

(4/3)πr³ = 2* 4 πr²

=>r =6

diameter = 2r =12

Answer 2

Answer:

hey here is your solution

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Step-by-step explanation:

$Q.3 \\ so \: here \: for \: a \: certain \: square \: tiles \\ its \: dimensions = 20.cm \times 20.cm \\ another \: dimensions \: are \: 5.m \times 4.m \\ = 500.cm \times 400cm \\ \\ so \: thus \: then \\ no.of \: tiles \: required = \frac{500 \times 400}{20 \times 20} \\ \\ = \frac{500 \times 400}{400} \\ \\ = 500 \\ \\ hence \: 500 \: such \: tiles \: are \: required$

$Q.4 \\ so \: we \: know \: that \\ volume \: of \: sphere = \frac{4}{3} \pi \: r {}^{3} \\ \\ curved \: surface \: area \: of \: sphere = 4\pi \: r {}^{2} \\ \\ so \: according \: to \: given \: condition \\ \frac{4}{3} \pi.r {}^{3} = 2 \times 4\pi.r {}^{2} \\ \\ = \frac{\pi.r {}^{3} }{3} = 2.\pi.r {}^{2} \\ \\ = \frac{r {}^{3} }{3} = 2r {}^{2} \\ \\ = r {}^{3} = 2 \times 3r {}^{2} \\ r = 6.units \\ \\ so \: thus \: then \\ diameter = 2.r \\ = 2 \times 6 \\ = 12.units$