Question

Answer for the 3 evaluate sums

Answer 1

Answer:

• 1 question

{(-2/3 )^2 }^ -2

1. 1 / (- 2 / 3 ) ^2

2 . 1/ 4 /9

3 . 9 / 4

done

Step-by-step explanation:

1 answar

{- ( 2/ 3 ) ^ 2 }^ - 2

step 1 : 1/((-2/3 ) ^ 2 )^2

step 2 : 1/16 /81

step 3 : 81 / 16

done .....

2 answar

step 1 : (1/3 ) ^-3-( 1/2 )^-3}÷(1/4)^-3

step 2 : (3)^3 - (2)^3 ÷ (4) ^3

step 3 : 27 - 8 ÷ 64

step 4 :19 × 1/64

step 5 : 19 /64

done

3 answar

step 1:{( 4/3 )^-1-(1/4 )^-1}^-1

step 2 : {1/4/3 - 1/1/4}^-1

step 3 : 4/3 - 1/4

step 5 : 12- 3 /12

step 6: 9 /12.....3 / 4