Question

Answer for the above question

Answer 1

Step-by-step explanation:

Given:

AB || DC

To Prove:

OA . CQ = OC . AP

Proof:

In ️△AOP & ️△COQ,

AB || DC ( Given )

∠ APO = ∠CQO ( Alternate interior angles )

∠PAO = ∠QCO ( Alternate interior angles )

∠AOP = ∠COQ ( Vertically opposite angles)

△️AOP ~ ️△COQ,

∴ corresponding sides would be proportional.

$\large \sf{ \frac{OA}{AP} = \frac{OC}{CQ} } \\ \\ \: \: \: \: \: \large \sf \therefore \: OA.CQ\: = \: OC.AP \: \: \: \: \: \green{proved.}</p><p>$