Question

answer for the question​

Answer 1

Answer:

Open intervel

Step-by-step explanation:

Condition 1 :

Log has domain > 0

$x - 3 > 0 \\ x \in(3 \: \: \: \: \infty )$

Condition 2 :

Denominator can't be zero

$log(x - 3) \neq0 \\x - 3 \neq1 \\ x \neq4$

Condition 3 :

Value in roots f(x) >/= 0

$\frac{ |x - 2| }{ log(x - 3) } \geqslant 0 \: \\ mod \: \: is \: always \: \: positive \\ log(x - 3) > 0 \\ x > 4$

Take intersection of all cases

$x \in( \: \: 4 \: \: , \: \: \infty \: \: )$