Question

Answer for the question please ​

Answer 1

Answer:

$\frac{ {2}^{2x - 1} }{ {2}^{x + 2} } = {2}^{2} \\ = > {2}^{2x - 1 - (x + 2)} = {2}^{2} \\ = > {2}^{2x - x - 1 - 2} = {2}^{2} \\ = > {2}^{x - 3} = {2}^{2} \\ = > compare \: powers \\ = > x - 3 = 2 \\ = > x = 2 + 3 \\ = > x = 5$

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