Question

answer for this attached question with steps pls​

Answer 1

Answer:

In Quad ABCD,

Diagonal are equal

hence

●3x-1 = 2x+2

x=3

● 5y+1 = 6y-1

y=2

hence X=3 AND Y =2

NOW

IN TRIANGLE ABC

A+B+C=180°

2x+15 +x+10+3x+5=180°

6x + 30 = 180°

6x= 150°

X= 25

Answer 2

Answer:

In parallelogram, diagonal bisect each other

let the point of intersection of AC and BC be O

so, AO=OC

5y+1=6y-1

5y-6y= -1-1

-y=-2

y=2

also,BO=OD

3x-1= 2(x+1)

3x-1=2x+2

3x-2x=2+1

x=3

in triangle sum of all angles is 180°

angle A+ angle B+ angle C= 180°

(x+10)°+(3x+5)°+(2x+15)°=180°

x+10+3x+5+2x+15=180°

6x+30=180°

6x=180-30

6x=150

x=25

HOPE IT HELPS YOU

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