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(8/3)^(2x+1)*(8/3)^5=(8/3)^(x+2)
=>(8/3)^(2x+6)=(8/3)^(x+2)
By equating the indices we get,
2x+6=x+2
=>x=-4
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=>(8/3)^(2x+6)=(8/3)^(x+2)
By equating the indices we get,
2x+6=x+2
=>x=-4
Mark me brainliest
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