Question

answer for this pls ​

Answer 1

Since the triangle is a right-angled triangle, so using Pythagorean Theorem

AC² = 52 + 12²

AC² = 25 + 144 +169

AC = 13

In triangle CBD and triangle CBA, the ZC is common to both the triangles, Angle CDB = Angle CBA = 90° so therefore Angle CBD = Angle CAB.

Therefore triangle CBD and triangle CBA are similar triangles according to AAA rule

so,

AC/BC = AB/BD

13/5=12/BD

BD=60/13

(¡) cos AngleDBC

base/ hypotenuse= BD/BC= 60/13/5

= 12/13

(¡¡). cot AngleDBA

base/ perpendicular = BD/AB = 60/13/12

=5/13