answer for this pls by quadratic equation
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Let the two digits be x,y
According to the question,
x.y = 20
y = 20/x
10x +y -9 = 10y + x
9x -9 = 9y
x - 1 = y
x - 1 = 20/x
x^2 - x = 20
Therefore,
x = 5
y =20/x = 4
10x + y = 54
According to the question,
x.y = 20
y = 20/x
10x +y -9 = 10y + x
9x -9 = 9y
x - 1 = y
x - 1 = 20/x
x^2 - x = 20
Therefore,
x = 5
y =20/x = 4
10x + y = 54
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