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x = 2+√3
1/x = 1/2+√3
Rationalise the denominator,
→ 1/(2+√3)×(2-√3)/(2-√3)
→ 2-√3/(2+√3)(2-√3)
→ 2-√3/(2²-√3²)
→ 2-√3/(4-3)
→ 2-√3/1
→ 1/x = 2-√3
According to the question, we need to find (x-1/x)³
→ {2+√3-(2-√3)}³
→ (2+√3-2+√3)³
→ {2√3)³
→ 2√3×2√3×2√3
→ 4(3)×2√3
→ 12×2√3
→ 24√3
Hope it helps
1/x = 1/2+√3
Rationalise the denominator,
→ 1/(2+√3)×(2-√3)/(2-√3)
→ 2-√3/(2+√3)(2-√3)
→ 2-√3/(2²-√3²)
→ 2-√3/(4-3)
→ 2-√3/1
→ 1/x = 2-√3
According to the question, we need to find (x-1/x)³
→ {2+√3-(2-√3)}³
→ (2+√3-2+√3)³
→ {2√3)³
→ 2√3×2√3×2√3
→ 4(3)×2√3
→ 12×2√3
→ 24√3
Hope it helps
Aaryadeep:
wrong
No, it's correct
Answered by
1
Hello friend
x=2+√3
1/x=1/(2+√3)
Rationalising the denominator we get
=2-√3/(2+√3)(2-√3)
=2-√3/2²-√3²
=2-√3/4-3
=2-√3/1
=2-√3
(x-1/x)³=(2+√3-(2-√3))³
=(2+√3-2+√3)³
=(2√3)³
=8×3√3
=24√3
Hope it helps
x=2+√3
1/x=1/(2+√3)
Rationalising the denominator we get
=2-√3/(2+√3)(2-√3)
=2-√3/2²-√3²
=2-√3/4-3
=2-√3/1
=2-√3
(x-1/x)³=(2+√3-(2-√3))³
=(2+√3-2+√3)³
=(2√3)³
=8×3√3
=24√3
Hope it helps
But I haven't
There's only one way in doing this
Thanks snehitha
I've corrected it! :)
really send the correct answer
Yeah it's the correct answer itself abhi
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