Question

Answer for this question​

Answer 1

793

Step-by-step explanation:

we know that (a+b)^3=a^3+b^3+3ab(a+b)

let a=2x, b=3y

substitute a and b in the above formula,then

(2x+3y)^3=(2x)^3+(3y)^3+3×(2x)(3y)(2x+3y)

from the problem we know that

2x+3y=13,xy=6

substitute these values in the above equation then

(13)^3=8x^3+27y^3+3×2×3×6(13)

8x^3+27y^3=13^3-3×2×3×6×13=793

8x^3+27y^3=793