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70° + 2x = 180° (Linear Pair = 180°)
2x = 180° - 70°
2x = 110°
x = 110°/2
x = 55°
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given:AOC is a linesegment
AOB=70°
BOC=2x°
value of x=
70°+2x°=180°. [sum of supplementry ang]
2x=180-70
x=110÷2
=55°
hence x is 55°
AOB=70°
BOC=2x°
value of x=
70°+2x°=180°. [sum of supplementry ang]
2x=180-70
x=110÷2
=55°
hence x is 55°
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