Question

answer for this question

Answer 1

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!}}}$
$<b><i><font face=Copper black size=4 color=blue>$
Here is your answer in the attachment


$\large{\red{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\underline{\underline{\underline{Hope \: it \: helps\: you}}}}}}}}}}}}}}}$

$\huge\boxed{\texttt{\fcolorbox{Red}{yellow}{Be brainly!!}}}$

$<marquee>$
$\huge\bf{\huge{\bf{\bf{@... MonarkSingh}}}}$

Answer 2

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!}}}$
$<b><i><font face=Copper black size=4 color=blue>$
Here is your answer.

Side of the Rhombus is 46 m
Altitude is 23 m

As we know the formula
Area of Rhombus = Base× Altitude
$= 46 \times 23 \\ = 1058 \: m {}^{2}$
Now Given Area of Rhombus is equal to Area of Square.

We know the formula
Let Side of Square is x m

Area of Square = (side)^2
$1058 = {x}^{2} \\ \\ x = \sqrt{1058} \\ \\ x = 32.52 \: m$
so side of Square is 32.52 m

Let the Diagonal of the Square is y m

By using Pythagoras Theorem.
Diagonal^2 = side^2 + side^2
${y}^{2} = (32.52) {}^{2} + (32.52) {}^{2} \\ \\ {y}^{2} = 1058 + 1058 \\ \\ {y}^{2} = 2116 \\ \\ y = \sqrt{2116} \\ \\ y = 46m$
Therefore Diagonal of the square is 46 m
and Side of the square is 32.52 m.

$\large{\red{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\underline{\underline{\underline{Hope \: it \: helps\: you}}}}}}}}}}}}}}}$

$\huge\boxed{\texttt{\fcolorbox{Red}{yellow}{Be brainly!!}}}$

$<marquee>$
$\huge\bf{\huge{\bf{\bf{@...rajeev378}}}}$