Question

answer for this question ( answer Yogeshwarkrishnan brainly sir)​

Answer 1

Answer:

standard equation for SHM

y=Asinwt

velocity=d(Asinwt)/dt=Awcoswt (1

acceleration=dv/dt=-Aw^2sinwt (2

given equation

y=0.4sin5πt

w is omega which is angular frequency

A is amplitudes

t is time

Amplitude=0.4

Angular frequency =w=5π

frequency

2πf=w

so f=w/2π=5/2=2.5

maximum velocity=wA=2πm/s. {from 1}

maximum acceleration w^2 ×A= (25×10×0.4)=100 m/s^2 {from 2}