answer for this question in book is angle OAB = 40 degree, angle OBA = 40 degree, angle AOB = 100 degree. correct answer will be marked as brainliest answer and thanks
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Step-by-step explanation:
In △OAB,
OA = OB [radii of same circle]
∠OBA = ∠OAB = 40° [∠s opp. to equal sides in a △ are equal]
Now, ∠OAB + ∠AOB + ∠OBA = 180° [angle sum properly of a △]
⇒ 40° + ∠AOB + 40° = 180°
⇒ ∠AOB = 100°
Therefore, ∠ACB = 50° [∵ angle subtended by an arc at the centre is double the angle subtended by it at the remaining part of the circle]
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