Question

Answer for this with steps please I will mark u as brainilist

Answer 1

Answer:

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(1)

$\frac{2y}{3} - \frac{5 {y}^{2} }{3} + \frac{5 {y}^{3} }{2}$

at y=1

$\frac{2(1)}{3} - \frac{5}{3} + \frac{5}{2}$

$\frac{2}{3} - \frac{10}{6} + \frac{15}{6}$

$\frac{2}{3} + \frac{5}{6} = \frac{4}{6} + \frac{5}{6} = \frac{9}{6} = \frac{3}{2}$

(2)

$\frac{ - 4}{3} + \frac{2 {y}^{2} }{3} - \frac{y}{2}$

At y=0

$\frac{ - 4}{3} + \frac{2}{3} - \frac{1}{2}$

$- \frac{2}{3} - \frac{1}{2}$

$\frac{ - 4 - 3}{6} = \frac{ - 7}{6}$

hence proved it