Math, asked by jatin8878, 1 year ago

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Answered by NishantMishra3
1
\huge\pink{\mathfrak{bonjour!!}}

¡)
(3x + 5)(5 - 2x) \\ \\ 15x - 6 {x}^{2} + 25 - 10x \\ \\ 5x - 6 {x}^{2} + 25

\huge\green{\mathfrak{========================}}

¡¡)
(x + 3y)(3x - y) \\ \\ 3 {x}^{2} - xy + 9xy - 3 {y}^{2} \\ \\ 3 {x}^{2} - 3 {y}^{2} + 8xy

\huge\blue{\mathfrak{========================}}

iii)
( {a}^{2} + b)(a + {b}^{2} ) \\ \\ {a}^{3} + {a}^{2} {b}^{2} + ab + {b}^{3}
\huge\yellow{\mathfrak{========================}}

iv)
( {p}^{2} - {q}^{2} )(2p + q) \\ \\ 2 {p}^{3} + {p}^{2} q - 2p{q}^{2} - {q}^{3}

\huge\blue{\mathfrak{========================}}

v)
(3x + 5)( {x}^{2} - 4x - 2) \\ \\ 3 {x}^{3} - 12 {x}^{2} - 6x + 5 {x}^{2} - 20x - 10 \\ \\ 3 {x}^{3} - 7 {x}^{2} - 26x - 10

\huge\light{\mathfrak{========================}}

vi)
(3 {x}^{2} + 4x - 7)(2 {x}^{2} + 3x + 4) \\ \\ 6 {x}^{4} + 9 {x}^{3} + 12 {x}^{2} + 8 {x}^{3} + 12 {x}^{2} + 16x - 14 {x}^{2} - 21x - 28 \\ \\ 6 {x}^{4} + 17 {x}^{3} + 10 {x}^{2} - 5x - 28

<marquee>
❤♥❤♥
\huge\red{\mathfrak{merci}}
♥❤♥❤

AryaRathode: yeh bonjour kaise likha?
AryaRathode: achaa❤️❤️
Answered by MonarkSingh
0
Here is your answer
(p {}^{2}  - q {}^{2} )(2p + q) \\  = 2p {}^{3}  + p {}^{2} q - 2pq {}^{2}  -  q {}^{3}  \\ (3x + 5)(x {}^{2}  - 4x - 2) \\  = 3x {}^{3}  - 12x {}^{2}  - 6x + 5x {}^{2}  - 20x - 10 \\  = 3x {}^{3}  - 7x {}^{2}  - 26x - 10 \\ (3x {}^{2}  + 4x - 7)(2x {}^{2}  + 3x + 4) \\  = 6x {}^{4}  + 9x {}^{3}  + 12x {}^{2}  + 8x {}^{3}  + 12x {}^{2}  + 16x - 14x {}^{2}  - 21x - 28 \\  = 6x {}^{4}  + 17x {}^{3}  + 10x {}^{2}  - 5x - 28
Hope it helps you
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