Math, asked by jha19212, 11 days ago

answer give the question pl​

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Answered by sarwa
0

Answer:

0

Step-by-step explanation:

Let P(x) = x³ - 3x²a + 2a²x + b

Given (x-a) is a factor of x³ - 3x²a + 2a²x + b

∴P(a)=0

x-a=0

x = a

⇒ (a)³ - 3a²a + 2a²a + b = 0

a³ - 3a³ +2a³ + b = 0

3a³ - 3a³ + b = 0

⇒ 0 + b= 0

⇒  b = 0

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