Question

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Answer 1

Given:-

• Initial velocity of Stone = 0m/s

• Height above the top of a window = 10m

• Height of window = 4.4

• Acceleration due to gravity = + 10m/s²

To Find:-

• The Time taken by the stone to cross the top to bottom of the window.

Formulae used:-

• s = ut + ½ × a × t²

Where,

• s = Distance
• u = Initial Velocity
• a = Acceleration
• t = Time

Now,

Time taken to cross the height of 10m

• → s = ut + ½ × a × t²

• → 10 = 0 × t + ½ × 9.8 × t²

• → 10 = 4.9t²

• → t² = 10/4.9

• → t² = 2.04

• → t (x) = 1.42s

• Hence, The time taken to cross the 10m height is 1.42s

Again,

• → Total Distance = 10 + 4.4

• → Total Distance = 14.4m

• → s = ut + ½ × a × t²

• → 14.4 = 0 × t + ½ × 9.8 × t²

• → 14.4 = 0 + 4.9t²

• → 14.4 = 4.9t²

• → t² = 14.4/4.9

• → √t² = √2.93

• → t ( y ) = 1.71s

Hence, The time taken by stone to cross whole height is 1.7s

Therefore,

• → Time taken to cross the top of window = y - x

• → 1.71 - 1.42

• → 0.29s

Therefore, The time taken by stone to

stone tocross from the top to bottom of the wwindo is 0.29s.