Question

answer hurry CH polynomial

Answer 1

ur writing is not understanding

Answer 2

P(x ) = 4x^3 + 3x^2 - 12ax - 5 is divided by x + 1

using remainder theorem

P ( - 1 ) = R1

P ( - 1 ) = 4x^3 + 3x^2 - 12ax - 5

= 4 ( -1 )^3 + 3 ( - 1 )^2 - 12 ( -1 ) ( a ) - 5

= - 4 + 3 + 12a - 5

= 12a - 6

so R1 = 12a - 6

When Q ( x ) = 2x^3 + ax^2 + 6x + 2 is divided by x + 2

using remainder theorem

R2 = Q ( - 2 )

so

Q ( -2 ) = 2x^3 + ax^2 + 6x + 2

= 2 ( - 2 )^3 + a ( - 2 )^2 + 6 ( -2 ) + 2

= - 16 + 4a - 12 + 2

= 4a - 26

so R2 = 4a - 26

3R1 + R2 + 28 = 0

3 ( 12a - 6 ) + 4a - 26 + 28 = 0

36a - 18 + 4a - 26 + 28 = 0

40a - 20 = 0

40a = 20

a = 1/2