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It has been given that PA parallel to the BC and AB is a transversal.
⇒∠ABC=∠PAB ...( alternate angles )
⇒a=50
Now, AB parallel to the DC and BC is a transversal.
⇒∠ABC+∠BCD=180
⇒50
+∠BCD=180
⇒∠BCD=130
Similarly, BC parallel to the DT and DC is a transversal.
⇒∠CDT=∠BCD ... ( alternate angles )
⇒b=130
Hence, a=50
and b=130
Sorry I use iOS so there is no degree sign here but pls make sure to denote the angles with degree sign
⇒∠ABC=∠PAB ...( alternate angles )
⇒a=50
Now, AB parallel to the DC and BC is a transversal.
⇒∠ABC+∠BCD=180
⇒50
+∠BCD=180
⇒∠BCD=130
Similarly, BC parallel to the DT and DC is a transversal.
⇒∠CDT=∠BCD ... ( alternate angles )
⇒b=130
Hence, a=50
and b=130
Sorry I use iOS so there is no degree sign here but pls make sure to denote the angles with degree sign
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