Answer:
If [Fe³+]=0.001mol.L-1, [ I- ]=0.001 mol.L−1, [Fe²+]=1 mol.L-1, what is spontaneous direction for the reaction 2Fe³+ + 2I- = 2Fe2+ + I2 ( φ⦵(Fe^ 3+ /Fe^ 2+ )=0.771V, φ⦵(I 2 /l^ - )=0.5355V) A.Forward direction B.Backward direction C.In equilibrium D.Can NOT be determined [ For clear understanding picture is attached ] * Incorrect response will be reported * Thank you.
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