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Class 11

>>Physics

>>Motion in a Plane

>>Projectile Motion

>>A particle is projected from the ground

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A particle is projected from the ground with an initial speed of v at an angle θ with horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is?

Hard

Solution

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Correct option is C)

For highest point-

T=(total−time)/2=

g

vsinθ

x=vcosθ×T=

g

v

2

sinθcosθ

y=

2g

v

2

sin

2

θ

displacement s=

x

2

+y

2

=

g

v

2

sin

2

θcos

2

θ+

4

sin

4

θ

v

av

=

T

s

=v

cos

2

θ+

4

sin

2

θ

⟹v

av

=

2

v

3cos

2

θ+1