Question

answer if you can

no vi and vii​

Answer 1

${\large{\pmb{\sf{\underline{Required \; Solution...}}}}}$

We are asked to find zero of,

${\pmb{\sf{1) \: p(x) \: = ax, \: a \ne 0}}}$

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${\pmb{\sf{2) \: p(x) \: = cx \: + d, \: c \ne 0, \: c \: \& \: d \: are \: real \: no.}}}$

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Accurate solution:

1) 0 is the zero of polynomial 1st

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2) ${\sf{\dfrac{-d}{c}}}$ is the zero of polynomial 2nd

Explanation:

${\pmb{\sf{1) \: p(x) \: = ax, \: a \ne 0}}}$

~ To solve this question we have to put x as zero to find the zero of p(x)

${\sf{\Rightarrow p(x) \: = ax, \: a \ne 0}}$

${\sf{\Rightarrow p(0) \: = a(0)}}$

${\sf{\Rightarrow 0 = 0}}$

${\sf{\Rightarrow Zero \: is \: 0}}$

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${\pmb{\sf{2) \: p(x) \: = cx \: + d, \: c \ne 0, \: c \: \& \: d \: are \: real \: no.}}}$

~ To solve this question we have to put p(x) as zero to find the zero of polynomial

${\sf{\Rightarrow p(x) \: = cx \: + d, \: c \ne 0, \: c \: \& \: d \: are \: real \: no.}}$

${\sf{\Rightarrow p(0) = cx \: + d}}$

${\sf{\Rightarrow 0 = cx \: + d}}$

${\sf{\Rightarrow \dfrac{-d}{c} \: = 0}}$

${\sf{\Rightarrow Zero \: is \: \dfrac{-d}{c}}}$