Question

answer in brief please with explanation...​

Answer 1

Answer:

Thus both the given cases are true.

Step-by-step explanation:

Case 1- (a)

x = -1/24

y = 3/4

|x| = 1/24

|y| = 3/4

x + y = -1/24 + 3/4

= 17/24

|x+y| = 17/24

|x| + |y| = 1/24 + 3/4

= 19/24

So ,

|x+y| <_ |x| + |y|

Case 2- (b)

xy = (-1/24)(3/4)

= -1/32

|xy| = 1/32

|x| • |y| = (1/24)(3/4)

= 1/32

So,

|xy| = |x| • |y|