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Step by step explanation:
Split the figure into two ∆ i.e, ∆BCD and ∆ADB.
Find the area of the ∆BCD :-
Here, s = semi perimeter i.e, 18cm.so,:-
The area of the ∆ BCD is 54cm^2.
Find the Area of ∆ABD :-
here AB is can be find out with the help of Pythagoras theorem.
So,
Now,
The area of the∆ABD using HERON'S formula:-
= 20cm.
So,
Total area of the figure is 54 + 20= 74 cm^2.
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