Math, asked by powerrangers26, 1 year ago

answer in copy please ​

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Answered by Anonymous
2

Answer:

\huge\bold\pink\star\purple{ANSWER :-}

Step by step explanation:

\huge\bold\blue\star\green{1st \: step}

Split the figure into two ∆ i.e, ∆BCD and ∆ADB.

Find the area of the ∆BCD :-

 \sqrt{s(s - a)(s - b)(s - c)}

Here, s = semi perimeter i.e, 18cm.so,:-

 \sqrt{18(18 - 15)(18 - 12)(18 - 9)}

 \sqrt{18(3)(6)(9)} =  \sqrt{2916}  = 54 {cm}^{2}

The area of the ∆ BCD is 54cm^2.

\huge\bold\green\star\purple{2nd \:\: step}

Find the Area of ∆ABD :-

here AB is can be find out with the help of Pythagoras theorem.

So,

 {17}^{2}  =  {(15)}^{2}  +  {ab}^{2}

ab = 8cm

Now,

The area of the∆ABD using HERON'S formula:-

 \sqrt{20(20 - 17)(20 - 15)(20 - 8)}

= 20cm.

So,

Total area of the figure is 54 + 20= 74 cm^2.

\bold\pink\star\purple{HOPE\: YOU \: LIKE \: THE \: ANSWER }

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