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we know that
sum of all angle of triangle=180°
In ∆ABC
angle A+angle B+angle C =180° ......(eq1)
In ∆DEF
angle D+angle E+angle F =180° .......(eq2)
on adding eq 1 and 2
angle A+B+C+D+E+F =360°(180+180)
HENCE PROVED
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