Question

Answer in details please
only 1st question
if you want you can answer second question also​

Answer 1

Answer:

1)$k {x}^{2} - 3x - 1 = 0$

$p( \frac{1}{2}) = k( \frac{1}{2} )^{2} - 3( \frac{1}{2}) - 1$

$\frac{k}{4} - \frac{6}{4} - \frac{4}{4} = 0$

$\frac{k - 6 - 4}{4} = 0$

$\frac{k - 10}{4} = 0$

$\frac{k}{4} = \frac{10}{4}$

$k =10$

$verification$

$10{x}^{2} - 3x - 1 = 0$

$10 {x}^{2} - 5x + 2x - 1 = 0$

$5x(2x - 1) + 1(2x - 1) = 0$

$(5x + 1)(2x - 1) = 0$

$x = \frac{ - 1}{5} \: or \: \frac{1}{2}$

2)x-y=3

x=y+3

2y+3x=19

(2x+3y)-(x-y) =-16

2(y+3)+3y=(-16)

2y+3y+6=(-16)

y=\frac{-22}{5}

x=\frac{-7}{5}

Hope it helps..

Mark as branliest...

Answer 2

Answer:

Instagram PR Milo mujhe mai ab brainly use nai krti

I'd :- zaranaaz 14