English, asked by seemakeshav2019, 2 months ago

Answer in one word-
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Answers

Answered by Simrankaur1025
1

Answer:

Given :-

Acceleration of bus (A) = 4 m/s²

Time taken (T) = 5 second

Initial velocity (U) = 0 m/s

To Find :-

Distance travelled

Solution :-

Here, we will use newton second Equation

\huge \boxed { \tt s = ut + \frac{1}{2} \times at {}^{2} }

s=ut+

2

1

×at

2

Here,

S = Distance

U = Initial velocity

T = Time

A = Acceleration

\sf \implies \: s = (0)(5) + \dfrac{1}{2} (4)(5) {}^{2}⟹s=(0)(5)+

2

1

(4)(5)

2

\sf \implies \: s = 0 + \dfrac{1}{2} \times 4 \times 25⟹s=0+

2

1

×4×25

\sf \implies \: s = 0 + 1 \times 2 \times 25⟹s=0+1×2×25

\sf \implies \: s = 0 + 50⟹s=0+50

\huge \sf \implies \: s = 50 \: m⟹s=50m

Hence,

Distance travelled by bus is 50 m.

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