Math, asked by ngawai813, 2 months ago

Answer in step by step please ​

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Answered by DhruvKunvarani
1

Answer:

(a) m²⁰/n¹⁵

(b) 1/q⁵

(c) y²/3x

Step-by-step explanation:

(a) \: ( {m}^{ - 4}  {n}^{3}  {)}^{ - 5}  \\  =  {m}^{ - 4 \times  - 5} \times   {n}^{3 \times  - 5}  \\  = {m}^{20}  {n}^{ - 15}  =  \frac{ {m}^{20} }{ {n}^{15} }

(b) \: ( {p}^{6}  {q}^{ - 2} )( {p}^{ - 6}  {q}^{ - 3} ) \\  =  {p}^{6}  \times {p}^{ - 6} \times {q}^{ - 2} \times {q}^{ - 3} \\  =  {p}^{6 - 6}  \times  {q}^{ - 2 - 3}  \\  =  {p}^{0}  \times  {q}^{ - 5}  =  \frac{1}{ {q}^{5} }

(c) \:  \frac{5 {x}^{ - 4} {y}^{8}  }{15 {x}^{ - 3} {y}^{6}}  \\  =  \frac{ {y}^{8} \times  {y}^{ - 6}  }{3 \times  {x}^{ - 3}  \times  {x}^{4} }  \\  =  \frac{ {y}^{8 - 6} }{3 \times  {x}^{ - 3 + 4} }  \\

=  \frac{ {y}^{2} }{3 {x}^{1} }  \: or \: \frac{ {y}^{2} }{3x }

Note that here exponential laws are used.

Hope it helps!

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