CBSE BOARD X, asked by 9615553431, 1 year ago

Answer in step wises..


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Answered by Nanish705
1
P(x,y)
atq
x=2y
p(2y,y)
Q(2,-5); R(-3,6)
PQ=PR
by distance formula
(2-2y)^2 + (-5-y)^2 =(-3-2y)^2 + (6-y)^2
(root will cancel )
4+4y^2-4y + 25+y^2+10y =9+4y^2 +12y + 36+y^2 - 12y (12 y cancels)
29+5y^2+6y = 45+5y^2
(5y^2 Cancel)

6y = 45-29
6y= 16
Y = 8/3
P(16/3, 8/3)

if hlped plz mrk brnliest ans.

9615553431: Thanks
Nanish705: No problem
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