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1. Simplify and verify the result for x = 2 and y = 1
(x+y)(2x+ y) + (x+ 2y)(x— y)
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Answered by Anonymous
22

Answer:

(i) 5xyz2 – 3zy

(ii) 1 + x + x2

(iii) 4x2y2 – 4x2y2z2 + z2

(iv) 3 – pq + qr – rp

(v)

(vi) 0.3 a – 0.6 ab + 0.5 b

Sol. (i) 5xyz2 – 3zy

In the expression 5xyz2 – 3zy, the terms are 5xyz2 and –3zy.

coefficient of xyz2 in the term 5xyz2 is 5.

coefficient of zy in the term –3zy is –3.

(ii) 1 + x + x2

In the expression 1 + x + x2, the terms are 1, x and x2.

Coefficient of x° in the term 1 is 1.

Coefficient of x in the term x is 1.

Coefficient of x2 is the term x2 is 1.

(iii) In the expression 4x2y2 – 4x2y2z2 + z2, the terms are 4x2y2, –4x2y2z2 and z2.

Coefficient of x2y2 in the term 4x2y2 is 4.

Coefficient of x2y2z2 in the term –4x2y2z2 is –4.

Coefficient of z2 in the term z2 is 1.

(iv) 3 – pq + qr – rp

In the expression 3 – pq + qr – rp, the terms are 3, –pq, qr and –rp

Coefficient of x° in the term 3 is 3.

Coefficient pq in the term –pq is –1.

Coefficient qr in the term qr is 1.

Coefficient rp in the term –rp is 1.

(v) In the expression the terms are

Coefficient of x in the term

Coefficient of y in the term

Coefficient of xy in the term – xy is – 1.

(vi) In the expression 0.3 a, – 0.6 ab and 0.5 b

Coefficient of a in the term 0.3a is 0.3.

Coefficient of ab in the term –0.6ab is

–0.6.

Coefficient of b in the term 0.5b is

Answered by Dɪʏᴀ4Rᴀᴋʜɪ
3

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1)(x+y)(2x+ y) + (x+ 2y)(x— y)

=>(x)(2x+ y)+y (2x+ y)+ (x) (x— y)+2y(x— y)

=>2x^2+xy+2xy+ y^2+ x^2-xy+2yx- 2y^2

=>3x^2+4xy- y^2 ANSWER

VERIFY

LHS

(x+y)(2x+ y) + (x+ 2y)(x-y)

x = 2 and y = 1

=>(2+1)(2×2+1)+(2+2×1)(2-1)

=>(3)(4+1)+(4)(1)

=>3×5+4=>15+4

=>19

RHS

3x^2+4xy-y^2

x = 2 and y = 1

=>(3×2^2)+(4×2×1)-1^2

=>(3×4)+(8×1)-1

=>12+8-1

=>20-1=>19

HOPE SO IT IS HELPFUL..❣️✌️..

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