Question

answer is 1-sin square0

Answer 1

Answer:

here is your answer army

Step-by-step explanation:

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Answer 2

$\orange{ \boxed{ \boxed{ \begin{array}{c | c} \sf \: Process & \sf \: Explantion \\ \underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }& \underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } \\ \\ \rm(1 + sin \theta)(1 - sin \theta)& \sf \: given \\ \\ \rm = {1}^{2} - {sin}^{2} \theta& \bf \because \: (x + y)(x - y) = {x}^{2} - {y}^{2} \\ \\ \rm = 1 - {sin}^{2} \theta& \\ \\ \rm = {cos}^{2} \theta& \bf \because \: {sin}^{2} \theta + {cos}^{2} \theta = 1 \\ \\ & \bf = > {cos}^{2} \theta = 1 - {sin}^{2} \theta \end{array}}}}$

Finally,

$\green{ \boxed{ \boxed{ \begin{array}{cc} \rm \: (1 + sin \theta)(1 - sin \theta) = {cos}^{2} \theta \: \end{array}}}}$