Question

answer is 2nd...show how to do​

Answer 1

Hey MATE!

Since both K1 are in parallel therefore equivalent K is given by :

1/K' = 1/K1 + 1/K1

1/K' = 1/2(K1)

Now the new K'and K2 are in series therefore Knet :

1/Knet = 1/2(K1) + 1/K2

Knet = [1/2(K1) + 1/K2]

Hope it helps

$<marquee><strong><em>HAKUNA </em></strong><strong><em>MATATA </em></strong><strong><em>:</em></strong><strong><em>)</em></strong><strong><em>)</em></strong>$

Answer 2

Answer:

hiii ayu this is the answer,hope it will help