Question

Answer is 31/32......... ​

Answer 1

Step-by-step explanation:

Given

$log_{ {x}^{2} }( {x}^{2} + 1) = \frac{log({x}^{2} + 1) }{2 log(x) } = 16$

$\frac{ log( \frac{ {x}^{2} + 1} {x} )}{32 log(x) } = \frac{1}{32} ( \frac{ log( {x}^{2} + 1 ) }{ log(x) } - \frac{ log(x) }{ log(x) } ) \\ = \frac{1}{32} (32 - 1) = \frac{31}{32}$