Question

answer is 328 cm square​

Answer 1

Solution :-

our polygon is divided into two parts trapezium and rectangle

$\sf \fbox \green{first \: let's \: find \: the \: area \: of \: trapezium}$

$\sf \: = Area = \frac{1}{2} (l + b) \times h$

$\sf \: = Area = \frac{1}{2}(10 + 18)(20 - 12)$

$\sf \: = Area = \frac{1}{2} \times (28) \times (8)$

$\sf \: = Area(1) = \sf \red{112 \: {cm}^{2} }$

$\sf \fbox \green{let's find the area of rectangle}$

$\sf \: = Area = lenght \: \times breadth$

$\sf \: = Area = 12 \times 18$

$\sf = Area(2) = \red {216 \: {cm}^{2} }$

$\sf \fbox \green{now let's find the total area}$

$\sf \: = Total \: Area \: = Area(1) + Area(2)$

$\sf \: = Total \: Area = 112 + 216$

$\sf \: = Total \: Area = \red{328 \: {cm}^{2} }$

$\sf \: answer \: → \red{328 \: {cm}^{2} }$