Math, asked by VaishnaviBijalwan, 4 months ago

answer is 6 , please give the solution . fast and correct . ​

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Answers

Answered by Flaunt
175

Question

 \sf \dfrac{2x - 3}{6}  -  \dfrac{x - 5}{2}  =  \dfrac{x}{6}

To find

value of x

\sf\huge\bold{\underline{\underline{{Solution}}}}

\sf \longmapsto \dfrac{2x - 3}{6}  -  \dfrac{x - 5}{2}  =  \dfrac{x}{6}

=>LCM of 2 and 6 is 6

\sf \longmapsto \dfrac{2x - 3 - 3(x - 5)}{6}  =  \dfrac{x}{6}

\sf \longmapsto \dfrac{2x - 3 - 3x + 15}{6}  =  \dfrac{x}{6}

\sf \longmapsto \dfrac{2x - 3x - 3 + 15}{6}  =  \dfrac{x}{6}

\sf \longmapsto \dfrac{ - x + 12}{6}  =  \dfrac{x}{6}

Now cross multiply to both side =>

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You can also solve by this

\sf =>-x+12=x[Bases are same on both sides so ,it gets automatically cancelled]

\sf =>12=2x

\sf=>x=6

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\sf \longmapsto6( - x + 12) = 6x

\sf \longmapsto - 6x + 72 = 6x

\sf \longmapsto72 = 12x

\sf \longmapsto \: x =  \dfrac{72}{12}  = 6

 \sf \huge \bold{ x = 6}

Check

\sf \longmapsto \dfrac{2(6) - 3}{6}  -  \dfrac{6 - 5}{2}  =  \dfrac{6}{6} =1

\sf \longmapsto \dfrac{12 - 3}{6} -  \dfrac{1}{2}

\sf \longmapsto \dfrac{9}{6}  -  \dfrac{1}{2}  =  \dfrac{9 - 3}{6}  =  \dfrac{6}{6}  = 1

Answered by Anonymous
10

Given :

:\boxed{\bf\dfrac{2x-3}{6}-\dfrac{x-5}{2}=\dfrac{x}{6}}

To Find :

The value of x.

Solution :

Analysis :

Here we have to solve the value of x by evaluating as per the signs.

Explanation :

\\ :\implies\sf\dfrac{2x-3}{6}-\dfrac{x-5}{2}=\dfrac{x}{6}

Taking LCM of 2 and 6 = 6,

Multiplying the quotient of the denominator with the numerator,

\\ :\implies\sf\dfrac{2x-3-3(x-5)}{6}=\dfrac{x}{6}

Expanding the brackets and changing the signs,

\\ :\implies\sf\dfrac{2x-3-3x+15}{6}=\dfrac{x}{6}

After evaluation,

\\ :\implies\sf\dfrac{-x+12}{6}=\dfrac{x}{6}

Cross Multiplying,

\\ :\implies\sf6(-x+12)=6x

Expanding the brackets,

\\ :\implies\sf-6x+72=6x

Transposing -6x to RHS,

\\ :\implies\sf72=6x+6x

After evaluation,

\\ :\implies\sf72=12x

\\ :\implies\sf\dfrac{72}{12}=x

\\ :\implies\sf\cancel{\dfrac{72}{12}}=x

\\ :\implies\sf6=x

\\ :\implies\boxed{\bf x=6.}

The value of x is 6.

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