Physics, asked by AR17, 1 year ago

Answer is (a)
⏩Explanation required⏪

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Answered by harishvermabaq
4
Hello Friend !

Explanation is given below :

Consider a small length dx at adistance x on the rod from the axis of rotation

mass of liquid in dx legth = dm = M/L dx

centrifugal force is acting  on dm mass
 
dF = dm x ω2
 
F = ∫df  =∫dm x ω2
 
=M/L ω2∫x dx        limit 0 to L 

=MLω2/2

this force is balance by normal reaction on fluid by other end
N =   MLω2/2
Hope this helps !

AR17: Thanks :-)
Answered by Anonymous
4
suppose a small length dx at a distance x on the rod from the axis of rotation
mass of liquid in dx legth = dm = M/L dx
centrifugal force is acting  on dm mass
 dF = dm x w2


 F = ∫df  =∫dm x w2

  =M/L w2∫x dx   
limit 0 to L

=MLw2/2
this force is balance by normal reaction on fluid by other end


N =   MLw2/2

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