answer is (b) but how??
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AB+CD+AD+BC=10+6+8+8=32 BECAUSE CB AND AB IS APPROXIMATELY EQUAL 32 IS NEARLY EQUAL TO B
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Drop a perpendicular from D to AB at L (let)
So DL = EF = 8 cm
And AL = (AB - CD)/2 = 2 cm
AD^2 = AL^2 + DL^2 = 68
AD = 2 _/17 = BC
So perimeter = 16 + 4 _/17 cm
So DL = EF = 8 cm
And AL = (AB - CD)/2 = 2 cm
AD^2 = AL^2 + DL^2 = 68
AD = 2 _/17 = BC
So perimeter = 16 + 4 _/17 cm
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