Chemistry, asked by kikibuji, 6 months ago

answer is option a .
explain it​

Attachments:

Answers

Answered by AbdulHafeezAhmed
3

Akka :D all the best for NEET!!!

Dr. Akka

The answer is option a) because the oxidation number of chlorine is less in Cl-O⁻. Since size of an atom is inversely proportional to effective nuclear charge, more the nuclear charge, less will be the size of the atom. If the size of the atom is less, then bond length is also less.

Oxidation number of chlorine is less in ClO⁻ (=1), so, its bond length will be more

ALL THE BEST AGAIN!!!

Answered by anjalimaurya3876
3

Answer:

[tx]<!DOCTYPE html>

<html lang="en">

<head>

<title>CUBE</title>

</head>

<body>

<div class="container">

<div id="cube">

<div class="front">☺️</div>

<div class="back">☺️</div>

<div class="right">☺️</div>

<div class="left">☺️</div>

<div class="top">☺️</div>

<div class="bottom">☺️</div>

</div>

</div>

<style>

body {

padding-left: 30%;

padding-top: 5%;

}

.container {

width: 200px;

height: 200px;

position: relative;

-webkit-perspective: 1000px;

-moz-perspective: 1000px;

}

#cube {

width: 100%;

height: 100%;

position: absolute;

-webkit-transform-style: preserve-3d;

-webkit-animation: rotatecube 10s infinite;

-moz-transform-style: preserve-3d;

-moz-animation: rotatecube 10s infinite;

}

#cube div {

width: 200px;

height: 200px;

display: block;

position: absolute;

border: none;

line-height: 200px;

text-align: center;

font-size: 50px;

font-weight: bold;

}

@-webkit-keyframes rotatecube {

0% { -webkit-transform: rotateX(0deg) rotateY(360deg) rotateZ(90deg); }

25% { -webkit-transform: rotateX(90deg) rotateY(270deg) rotateZ(180deg); }

50% { -webkit-transform: rotateX(180deg) rotateY(180deg) rotateZ(0deg); }

75% { -webkit-transform: rotateX(270deg) rotateY(90deg) rotateZ(360deg); }

100% { -webkit-transform: rotateX(360deg) rotateY(0deg) rotateZ(270deg); }

}

@-moz-keyframes rotatecube {

0% { -moz-transform: rotateX(0deg) rotateY(360deg) rotateZ(90deg); }

25% { -moz-transform: rotateX(90deg) rotateY(270deg) rotateZ(180deg); }

50% { -moz-transform: rotateX(180deg) rotateY(180deg) rotateZ(0deg); }

75% { -moz-transform: rotateX(270deg) rotateY(90deg) rotateZ(360deg); }

100% { -moz-transform: rotateX(360deg) rotateY(0deg) rotateZ(270deg); }

}

.front {

background: rgba(255,0,0,.5);

}

.back {

background: rgba(0,255,0,.5);

}

.right {

background: rgba(0,0,255,.5);

}

.left {

background: rgba(0,255,255,.5);

}

.top {

background: rgba(255,0,255,.5);

}

.bottom {

background: rgba(255,255,0,.5);

}

#cube .front {

-webkit-transform: rotateY(0deg ) translateZ( 100px );

-moz-transform: rotateY( 0deg ) translateZ( 100px );

}

#cube .back {

-webkit-transform: rotateX( 180deg ) translateZ( 100px );

-moz-transform: rotateX( 180deg ) translateZ( 100px );

}

#cube .right {

-webkit-transform: rotateY( 90deg ) translateZ( 100px );

-moz-transform: rotateY( 90deg ) translateZ( 100px );

}

#cube .left {

-webkit-transform: rotateY( -90deg ) translateZ( 100px );

-moz-transform: rotateY( -90deg ) translateZ( 100px );

}

#cube .top {

-webkit-transform: rotateX( 90deg ) translateZ( 100px );

-moz-transform: rotateX( 90deg ) translateZ( 100px );

}

#cube .bottom {

-webkit-transform: rotateX( -90deg ) translateZ( 100px );

-moz-transform: rotateX( -90deg ) translateZ( 100px );

}

</style>

</body>

</html>[/tex]

Similar questions