Math, asked by googleuser687, 1 year ago

answer is question fast

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Answered by siddhartharao77
2

Given : (x^2 - 3x)^2 - 8(x^2 - 3x) - 20.

= > x^4 + 9x^2 - 6x^3 - 8x^2 + 24x - 20

= > x^4 - 6x^3 + x^2 + 24x - 20

= > x^4 - 5x^3 - x^3 + 5x^2 - 4x^2 + 20x + 4x - 20

= > x^4 - 5x^3 - 4x^2 + 20x - x^3 + 5x^2 + 4x - 20

= > x(x^3 - 5x^2 - 4x + 20) - 1(x^3 - 5x^2 - 4x + 20)

= > (x - 1)(x^3 - 5x^2 - 4x + 20)

= > (x - 1)(x^2(x - 5) - 4(x - 5))

= > (x - 1)(x^2 - 4)(x - 5)

= > (x - 1)(x^2 - 2^2)(x - 5)

= > (x - 1)(x + 2)(x - 2)(x - 5)


Hope this helps!.


siddhartharao77: :-)
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