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Step-by-step explanation:
4^x = 5^y = 20^z = K
4^x = K
take log both sides
xlog4 = logK
log4 = logK/ x ------(1)
similarly,
5^y = K
log5 = logK/y ------------(2)
and ,
20^z = K
z = logK/log20
= logK/log(5×4)
= logK/{ log5 + log4}
put eqns (1) and (2)
z = logK/{ logK/x + logK/y}
= 1/( 1/x + 1/y )
= xy/( x + y)
hence, z = xy/( x + y)
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