Question

answer is you can
fast​

Answer 1

Answer:

the answers is

$= {x}^{2b}$

Step-by-step explanation:

given:

$( \frac{ {x}^{ \frac{a}{a - b} } }{ {x}^{ \frac{a}{a - b} } } \times \frac{ {x}^{ \frac{b}{b - a} } }{ {x}^{ \frac{b}{b - a} } } )$

cancelling the like terms

$= \frac{ {x}^{ \frac{a}{a - b} } }{ {x}^{ \frac{a}{a + b} } }$

$if \: we \: have \: \ \: : {x}^{ \frac{a}{b} } \\ thenw \: can \: write \: it \: as \: {x}^{ \frac{a}{b} } = \frac{ {x}^{a} }{ {x}^{b} }$

then we can write the above equation as

$\frac{ {x}^{ \frac{a}{a - b} } }{ {x}^{ \frac{a}{a + b} } } = \frac{ {x}^{a} }{ {x}^{a - b} } \times \frac{ {x}^{a + b} }{ {x}^{a} }$

$= \frac{ {x}^{a + b} }{ {x}^{a - b} }$

$= \frac{ {x}^{a \ } \times {x}^{b} \times {x}^{b} }{ {x}^{a} }$

$= {x}^{2b}$