Math, asked by sardarmeena78, 8 months ago

answer it
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Answers

Answered by blackmatrix20
0

Answer:

(i): (x^2+1)*(x^2+4)

(iii): 3x^2+2x-1

Step-by-step explanation:

(i): using a^2+2ab+b^2=(a+b)^2 factor the expression

(x^2+1)^2+3(x^2+1)

factor out x^2+1 from the expression

(x^2+1)*(x^2+1+3)

add the numbers

(solution): (x^2+1)*(x^2+1+3) = at the top.

(iii):

(x^2+2x+1)+2(x^2-1)

remove unnecessary parentheses

x^2+2x+1+2(x^2-1)

Distribute 2 through the parentheses

x^2+2x+1+2x^2-1

(solution): 3x^2+2x-1

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