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Answer:
(i): (x^2+1)*(x^2+4)
(iii): 3x^2+2x-1
Step-by-step explanation:
(i): using a^2+2ab+b^2=(a+b)^2 factor the expression
(x^2+1)^2+3(x^2+1)
factor out x^2+1 from the expression
(x^2+1)*(x^2+1+3)
add the numbers
(solution): (x^2+1)*(x^2+1+3) = at the top.
(iii):
(x^2+2x+1)+2(x^2-1)
remove unnecessary parentheses
x^2+2x+1+2(x^2-1)
Distribute 2 through the parentheses
x^2+2x+1+2x^2-1
(solution): 3x^2+2x-1
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