Question

answer it!!!!!!!!!!!!​

Answer 1

Answer:

see the proof

Step-by-step explanation:

given ∆APD and∆BQC are equilateral triangle

then all sides and angles are equal in that triangles

we can write

<APD = <BQC = <PAD = <QBC = <ADP = < BCQ ........1

<PAB = <PAD + <DAB

= < BCQ + <DAB (by 1)

= <BCQ + < BCD. ( by parallel line angles or in

parallelogram opposite angles are

equal)

= < QCD

therefore <PAB = <QCD