Question

answer it ...................​

Answer 1

Explanation:

$\sf q = 10 \mu C \: \: \: \: r = 3 m \\ \\ \sf Electric \:potential\:due\:to\: uniformly\:charged \:ring \:is \\ \\ \sf \boxed{\bold{\red {V= \frac{kq}{\sqrt{{x}^{2}+{r}^{2}}}}}} \\ \\ \sf V = \frac{ 9 × {10}^{9} × 10 × {10}^{-6}}{\sqrt{{3}^{2}+{4}^{2}}} \\ \\ \sf V = 18 × {10}^{3} V \\ \\ \sf \bold{\underline{\underline{Correct\: Answer\:is\:V=18×{10}^{3}}}}$

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