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Answer:
The answer is (5i-4j+6k) + t (3i+7j+2k)
Step-by-step explanation:
Let ( x-5) /3 =( y+4)/7= (z-6)/2 = t
Where t is constant
So
x = 3t +5
y = 7t - 4
Z = 2t + 6
So the required vector equation is
= xi + yj +zk
= (3t +5) i + ( 7t - 4) j + ( 2t + 6) k
= (5i-4j+6k) + t (3i+7j+2k)
Where t is a parameter
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