Math, asked by modifan, 1 year ago

answer it........................

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Answered by pulakmath007
2

Answer:

The answer is (5i-4j+6k) + t (3i+7j+2k)

Step-by-step explanation:

Let ( x-5) /3 =( y+4)/7= (z-6)/2 = t

Where t is constant

So

x = 3t +5

y = 7t - 4

Z = 2t + 6

So the required vector equation is

= xi + yj +zk

= (3t +5) i + ( 7t - 4) j + ( 2t + 6) k

= (5i-4j+6k) + t (3i+7j+2k)

Where t is a parameter

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Answered by Anonymous
4

HII MATE :-)

REFER TO ATTACHMENT

HOPE IT HELPS,

PLEASE THANK , FOLLOW AND MARK AS BRAINLIEST.

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