Question

Answer it.....................​

Answer 1

✪ᴀɴsᴡᴇʀ✪

• $[K] = 3$

★ᴇxᴘʟᴀɪɴᴀᴛɪᴏɴ★

$f(x) = \frac{ \sin(x + 9) }{ \cos(x) }$

$f(x) = \frac{ \sin(x) \cos(9) + \cos(x) \sin(9) }{ \cos(x) }$

$f(x) = \tan(x) \cos(9) + \sin(9)$

Since period of tan(x) is π, period of f(x) is π

$⇒ K = π$

$⇒ [K] = [π]$

$⇒ [K] = 3$